Merge branch 'researchML' into 'dev'

Research ml

See merge request igrannonica/neuronstellar!6

1 files changed, 61 insertions, 0 deletions

diff --git a/sandbox/testAppNevena/Front/node_modules/abbrev/abbrev.js b/sandbox/testAppNevena/Front/node_modules/abbrev/abbrev.js
new file mode 100644
index 00000000..7b1dc5d6
--- /dev/null
+++ b/sandbox/testAppNevena/Front/node_modules/abbrev/abbrev.js
@@ -0,0 +1,61 @@
+module.exports = exports = abbrev.abbrev = abbrev
+
+abbrev.monkeyPatch = monkeyPatch
+
+function monkeyPatch () {
+  Object.defineProperty(Array.prototype, 'abbrev', {
+    value: function () { return abbrev(this) },
+    enumerable: false, configurable: true, writable: true
+  })
+
+  Object.defineProperty(Object.prototype, 'abbrev', {
+    value: function () { return abbrev(Object.keys(this)) },
+    enumerable: false, configurable: true, writable: true
+  })
+}
+
+function abbrev (list) {
+  if (arguments.length !== 1 || !Array.isArray(list)) {
+    list = Array.prototype.slice.call(arguments, 0)
+  }
+  for (var i = 0, l = list.length, args = [] ; i < l ; i ++) {
+    args[i] = typeof list[i] === "string" ? list[i] : String(list[i])
+  }
+
+  // sort them lexicographically, so that they're next to their nearest kin
+  args = args.sort(lexSort)
+
+  // walk through each, seeing how much it has in common with the next and previous
+  var abbrevs = {}
+    , prev = ""
+  for (var i = 0, l = args.length ; i < l ; i ++) {
+    var current = args[i]
+      , next = args[i + 1] || ""
+      , nextMatches = true
+      , prevMatches = true
+    if (current === next) continue
+    for (var j = 0, cl = current.length ; j < cl ; j ++) {
+      var curChar = current.charAt(j)
+      nextMatches = nextMatches && curChar === next.charAt(j)
+      prevMatches = prevMatches && curChar === prev.charAt(j)
+      if (!nextMatches && !prevMatches) {
+        j ++
+        break
+      }
+    }
+    prev = current
+    if (j === cl) {
+      abbrevs[current] = current
+      continue
+    }
+    for (var a = current.substr(0, j) ; j <= cl ; j ++) {
+      abbrevs[a] = current
+      a += current.charAt(j)
+    }
+  }
+  return abbrevs
+}
+
+function lexSort (a, b) {
+  return a === b ? 0 : a > b ? 1 : -1
+}