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authorRavinou <39600829+Ravinou@users.noreply.github.com>2021-10-15 18:13:06 +0200
committerGitHub <noreply@github.com>2021-10-15 18:13:06 +0200
commite05e633014628a65942cffab66f68228b6e17f7a (patch)
treef7598f1792f2c68a85e166c1153d8f3e59dbf948 /LICENSE
parent5f4c2f8a389017fcffa8f1b53add02a9b014b224 (diff)
Better IPv4 detection (#278)
On some systems like Hetzner VM cloud i have a Point-to-Point interface so i have a peer address on the same line as my public IPv4 (look at peer here : https://linux.die.net/man/8/ip ) An example of `ip a` with peer is : ``` 2: eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast state UP group default qlen 1000 link/ether 96:00:00:a2:88:c2 brd ff:ff:ff:ff:ff:ff altname enp0s3 inet XX.XX.XX.XX peer XX.XX.XX.XX/32 brd XX.XX.XX.XX scope global eth0 valid_lft forever preferred_lft forever inet6 fe80::9400:ff:fea2:88c2/64 scope link valid_lft forever preferred_lft forever ``` With a peer, the output of the command line 74 is : `XX.XX.XX.XX peer XX.XX.XX.XX` I just modify this line with awk to print only the first field which is always the IPv4. I think it's correct and it's work like a charm when there is a peer or not now. But tell me if it's not good for you :) Thanks for your work !
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